Chemistry

Solution

Solution


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The following relationship was derived for the gross reaction rate.

rbr=kp(kdkt)12[I.]12[M.]rbr = Gross reaction speedkp = Rate constant of the growth reactionkd = Rate constant of initiator decaykt = Rate constant of the termination[I.] = Initiator concentration[M.] = Monomer concentration

As the gross reaction rates for the polymerizations with full initiator concentration [I.]1and 25% initiator concentration [I.]2=14[I.]1should be the same, the following equation must apply.

kp(kdkt)12[I.]112[M.]1=kp(kdkt)12[I.]212[M.]2[M.]1= original monomer concentration[M.]2 = wanted monomer concentration

It follows:

[I.]112[M.]1=[I.]212[M.]2=(14[I.]1)12[M.]2=12[I.]112[M.]2

Dissolve after [M.]2results

[M.]2=2[M.]1


Video: The Solution. Craig Bierlys Wanderlust Way (July 2022).


Comments:

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  2. Gaynor

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  3. Moogujin

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